digitalWrite(LED_BUILTIN,0) has inverted logic

[FabioM3]

Describe the bug
The logic on "digitalWrite(LED_BUILTIN, 0)" is inverted, when I use an external led it works, but for the LED_BUILTIN it turns OFF the led with 1 and ON with 0.

To Reproduce

`#define botaoLigaDesliga A3
short ligado = 0;
unsigned long tempoPassadoBotao = 0;

void setup() {
pinMode(botaoLigaDesliga, INPUT_PULLDOWN);
pinMode(LED_BUILTIN, OUTPUT);

digitalWrite(LED_BUILTIN, ligado);
}

void loop() {
if (digitalRead(botaoLigaDesliga)) {
if (millis() - tempoPassadoBotao >= 2000) {
if (ligado) {
ligado = 0;
} else {
ligado = 1;
}

  digitalWrite(LED_BUILTIN, ligado);
  tempoPassadoBotao = millis();
  Serial.print("Botão apertado - ");
  Serial.println(ligado);
}

}
}`

Steps to reproduce the behavior:

1. Plug.
2. Press BTN on A3 to change the state of the led.
3. See on serial the 0 or 1 and compare with the led.

Expected behavior
The led needs to be OFF with 0 and on with 1.

Desktop (please complete the following information):

• OS: Windows 10
• Arduino IDE version: [e.g. 2.3]
• STM32 core version: [e.g. 2.9]

[fpistm]

Hi @FabioM3
This is not an issue. This is only linked to the hardware, the Active state is inverted

Logical level is:
HIGH --> LED OFF
LOW --> LED ON

[FabioM3]

Oh, I thought it was something hardware related, but I haven't found anything related to this in my searches.
At least now people have this post as a reference to this bad design.
Thanks.